This is a screenshot of the question. The diagram isn't perfect but that's not really the problem here. The question is: you are given the curve y = x2 and you have three points: A, B and C, where B is the origin (0, 0). Find A and C such that the triangle is equilateral.
Although it took me a while (due to a idiotic mistake) my two methods are (1) using the length of the sides and (2) using trigonometry
Solution for (1)
Now this is where it gets interesting. Dr Munro then suggested that from here he would ask students if this triangle could be similar to a 3, 4, 5 triangle (obviously no, due to the proportions being completely different). Then he wants us to MAKE IT INTO ONE!
I haven't got around to it yet because I have been annoyingly busy today (which, of course, means I was yet again unsuccessful at planning my time) but I definitely have some ideas. I'm going to have a go at it and update ASAP.



No comments:
Post a Comment